well i'm in summer school for algebra although i don't have to take it it's just if i did'nt take it i'm stuck for 2 period algebra:( see i get a test every day and my teacher is stubborn it's mostly a alone class work stuff and well if any one can help me thank's i'm not that good  at math but at every other subject i am but what i hate about math that you can be good at the other sub's but math bad in that it make's you look like a D.AZZ i hate that:(

so if you can explain the following problem and how to solov similar problems thanks 3x+3=2(x-3) 2. 6x-2=2(2x+4) i mean that's easy stuff but i have bad idc teach's so yeah if any one can help with explaining problems like this thank you *don't rub it in plz*

ok the problems go as following srry for the mishaps 3x+3=2(x-3) and no. 2. is 4x+6=2(3x-4)

sorry about that

Are these two different problems?  Are you trying to solve for x?  If they are two seperate ones and you are solving for x.  First, multiply 2(x-3) to get 3x+3=2x-6   then, you can get the xs to the same side.  so, subtrack from the right and add to the left.  3x+3+2x=2x-6-2x  so, you have 5x+3=-6  then subtract the 3 from the left and add to the right... 5x =-3   Finally, x= -3/5



If they are somehow one problem and you need more help please explain more in your quesiton.

Are the problems you are asking for explanations on

3x+3=2(x-3)

and

6x-2=2(2x+4)?



Assuming so, in both equations they are saying that

3x+3 will equal the same number as 2(x-3).

The same goes for the second equation.

Therefore, you know that if you join like terms, you can find what both sides of the equations equal.

To do so, first multiply out the sides of the equations with parenthesis.

For the first equation:

3x+3=2x-6      b/c you multiply the two by everything in parenthesis.

For the second equation:

6x-2=4x+8      

Now you want to get the x's on one side of the equal sign and the constant on the other side.

To do this, you must make the terms in the equation cancel out.

For the first equation:

3x+3=2x-6          -so first handle the x terms

-3x    -3x              -subtract 3x from the left side to cancel it out (making it equal zero on the left. Once you do that, you must do the same to the other side. So subtract 3x on the right as well.

After doing this, you get 3=-x-6 b/c 2-3 leaves one negative.

Now lets handle the constant:

  3=-x-6

+6     +6                -do the same thing as you did above with the constant. Then you get,

9=-x                      -now divide the 9 by the term in front of the variable.

 9/-1  which equals -9 so x=-9

Now you have completed the first equation. Do the same for the second one.

Second Equation:

 6x-2=4x+8

-6x    -6x

so you get      

-2=-2x+8

-8         -8                -b/c you add like terms.

which equals

-10=-2x

so dividing -10 by -2 you find that x equals 5



I hope that helps, and if you need any further explanation, please feel free to ask.